Grades 1-2 Video Solutions 2019-2019Levels12prob14

Video Transcription

Video Summary

The problem involves determining which shape, made of four connected cubes, has the smallest paintable surface area. Each cube has six faces, with some covered due to being glued together. By examining each shape, the uncovered faces are counted and totaled for all cubes in each shape. Calculating the uncovered faces for each shape results in totals of 18 for A, 16 for B, 18 each for C, D, and E as well. Shape B, with a total of 16 uncovered faces, has the smallest area to be painted. Thus, the answer is shape B.

Keywords

smallest paintable surface

four connected cubes

uncovered faces

shape B

surface area calculation