Grades 1-2 Video Solutions 2021-video 2021 1-2/19

Video Transcription

Video Summary

In this problem, the numbers 2, 3, 4, 5, and 6 must be placed into two boxes such that the sums of each box are equal. The total sum of these numbers is 20, so each box must sum to 10. The task is to determine which number must be in the box with the number 4. By attempting different combinations, it is determined that only the combination of 4 and 6 results in a sum of 10. Therefore, the number 6 must be in the box with the number 4. The answer is C: only 6.

Keywords

number partitioning

equal sum boxes

combinatorics

problem-solving

math puzzle