Grades 11-12 Video Solutions 2010-11&12 Video Solutions 2010 problem22

11&12 Video Solutions 2010 problem22

Video Transcription

Video Summary

The problem involves 100 runners who finished a race, each providing their placement number totaling 4000 instead of the correct sum of 5050. To find the minimum number of incorrect responses, we calculate the difference of 1050 (5050 - 4000) and distribute it among the fewest high-numbered responses. By summing from 100 downwards, it is determined that 12 incorrect responses suffice, with 100 down to 89, which exceeds the required difference. Thus, the smallest number of incorrect responses is 12.

Keywords

race

runners

incorrect responses

placement numbers

sum discrepancy