Grades 11-12 Video Solutions 2012-2012_11-12

Video Transcription

Video Summary

In a theater, all tickets for the first-row seats were sold, but one ticket was incorrectly sold twice, leading to a sum of seat numbers equaling 857. To find the seat number sold twice, the formula for the sum of the first \( n \) consecutive numbers, \( n(n+1)/2 \), was used. Testing \( n=40 \) yields a sum of 820. Subtracting 820 from 857 results in 37, indicating that seat 37 was sold twice. Thus, the duplicated seat number is 37.

Keywords

theater

tickets

duplicate

seat number

sum formula