Grades 11-12 Video Solutions 2012-2012_11-12

Video Transcription

Video Summary

The problem involves finding the smallest number of operations needed to return a fraction to its original form after altering the numerator and denominator. Starting with the fraction 7/8, the operations are: increasing the numerator by 8, and increasing the denominator by 7. To solve 7 + 8x over 8 + 7y = 7/8 with minimal operations, we determine that x must be a multiple of 49 and y a multiple of 64. The smallest solution for x and y, thus minimizing x + y, is x = 49 and y = 64, resulting in a total of 113 operations.

Keywords

fraction

operations

numerator

denominator

solution