Grades 11-12 Video Solutions 2013-Levels 11&12 Video Solutions 2013 problem6

Levels 11&12 Video Solutions 2013 problem6

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The problem involves a linear function \( F \) where the difference \( F(2013) - F(2001) = 100 \). To find \( F(2031) - F(2013) \), we use the linearity property. By examining increments, \( F(18) \) equates to \( \frac{3}{2} \times F(12) \), therefore \( F(12) = 100 \) and \( F(18) = 150 \). Hence, the desired value is 150.