Grades 11-12 Video Solutions 2014-11&12 Video Solutions 2014 problem21

11&12 Video Solutions 2014 problem21

Video Transcription

Video Summary

The problem involves finding 10 different positive integers, with exactly 5 divisible by 5 and 7 by 7. The goal is to determine the minimum possible value for the largest number, m. The example examined various combinations including numbers divisible by both 5 and 7 (like 35, 70) and explored how to adjust the list to satisfy the conditions. Attempting to use numbers smaller than 70 like 63 was unsuccessful in meeting all criteria without exceeding 10 numbers, confirming that the smallest m achievable is indeed 70, leading to the conclusion that the solution is option E.

Keywords

positive integers

divisible

minimum value

largest number

combinations