Grades 11-12 Video Solutions 2023-2023_11-12

2023_11-12_12

Video Transcription

Video Summary

The problem involves finding the sum of the digits of \( n \) when \( n! = 6! \times 7! \). By breaking down the factorials and rearranging them, the solution identifies that \( n! = 10! \). Since \( n = 10 \), the sum of its digits, \( 1 + 0 \), equals 1. The final answer is 1.