Grades 11-12 Video Solutions 2024-2024_11-12

Video Transcription

Video Summary

Two candles of equal length burn at different rates: one in 4 hours, the other in 5. We seek the time when the slower-burning candle is three times the length of the faster one. Given the initial length as L, the faster candle decreases by L/4 per hour and the slower by L/5 per hour. After T hours, the lengths become L-TL/4 and L-TL/5, respectively. Solving for when the slower candle is three times the faster candle's length, we find it occurs after 40/11 hours.

Keywords

candles

burning rates

length comparison

time calculation

mathematical solution