Grades 11-12 Video Solutions 2026-2026_11-12

Video Transcription

Video Summary

The transcript solves a digit-counting problem for three-digit numbers \(a,b,c\) satisfying a given equation. It concludes that \(a\) must be a perfect square digit: 1, 4, or 9. For \(a=1\), there are 9 valid digit pairs \((b,c)\); for \(a=4\), there are 4; and for \(a=9\), there are 3. Adding these gives \(9+4+3=16\). So the total number of such three-digit numbers is 16, which corresponds to choice E.

Keywords

digit-counting

three-digit numbers

perfect square digits

combinatorics

number theory