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Grades 11-12 Video Solutions 2026
2026_11-12_13
2026_11-12_13
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Video Transcription
Video Summary
The problem asks for the missing length in a square with two perpendicular lines and three given segments. By dropping altitudes from both diagonals, two right triangles are formed that are congruent because the diagonals are perpendicular. Let the short leg be \(x\). Since opposite paths equal the square’s side length, we get \(4.8 + x + 7.7 = 6.2 + x + ?\). The \(x\) cancels, leaving the unknown as \(6.3\). So the answer is <strong>D. 6.3</strong>.
Keywords
square geometry
perpendicular diagonals
right triangles
missing length
congruent triangles
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