Grades 5-6 Video Solutions 2015-Level 5&6 Video Solutions 2015 problem23

Level 5&6 Video Solutions 2015 problem23

Video Transcription

Video Summary

The maximum number of people that can live on Jump Street, with nine houses and the condition that any two neighboring houses have at most six people, is 29. By alternating between five and one inhabitants (five in one house and one in its neighbor), the sequence maximizes the total population without leaving any house uninhabited. Calculations show that the arrangement of five people in five houses and one person in four houses yields 29, which is the highest possible number meeting the given conditions. Thus, the correct answer is 29 people.

Keywords

Jump Street

maximum population

neighboring houses

inhabitants arrangement

population optimization