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Grades 5-6 Video Solutions 2015
Level 5&6 Video Solutions 2015 problem23
Level 5&6 Video Solutions 2015 problem23
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Video Transcription
Video Summary
The maximum number of people that can live on Jump Street, with nine houses and the condition that any two neighboring houses have at most six people, is 29. By alternating between five and one inhabitants (five in one house and one in its neighbor), the sequence maximizes the total population without leaving any house uninhabited. Calculations show that the arrangement of five people in five houses and one person in four houses yields 29, which is the highest possible number meeting the given conditions. Thus, the correct answer is 29 people.
Keywords
Jump Street
maximum population
neighboring houses
inhabitants arrangement
population optimization
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