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Grades 5-6 Video Solutions 2021
video 2021 5-6/12
video 2021 5-6/12
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Video Transcription
12. The map shows three bus stations at points A, B, and C, shown here. A tour from station A to the zoo to the port and back to A is 10 kilometers long. A tour from station B to the park to the zoo and back to B is 12 kilometers long. A tour from station C to the port and then the park and back to C is 13 kilometers long. Also, a tour from the zoo to the park to the port and then back to the zoo is 15 kilometers long. How long is the shortest tour from A to B to C, A to B to C, and then back to A? Okay, so the shortest tour from A to B to C to A is going to be this tour that basically traverses this perimeter of our map right here. So what we can do is we can sum up the lengths of the A, B, and C tours. Those do give us the tour of the map. They give us all of this, but they also give us this length in here. They give us this length and this length. So it gives us a little bit more than this whole perimeter length and that value is 10 plus 12 plus 13, which is 35. However, we also get this inner perimeter included, but guess what? They've given us the perimeter of the inner shape. So we subtract that from our sum to find the total length of this outer perimeter. So 10 plus 12 plus 13, this is tour A plus tour B plus tour C minus the inner tour gives us 20 and that is our answer B.
Video Summary
The problem involves calculating the shortest tour from bus stations A to B to C and back to A, considering multiple given routes and distances. Tours from A, B, and C with various stops total 35 kilometers and include extra internal routes. The inner tour distance provided is 15 kilometers. To find the outer perimeter only, subtract the internal tour from the total: 35 - 15 = 20 kilometers. Thus, the shortest tour from A to B to C and back to A is 20 kilometers.
Keywords
shortest tour
bus stations
routes
distances
perimeter
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