Grades 5-6 Video Solutions 2026-2026_5-6

2026_5-6_15

Video Transcription

Video Summary

The seven numbers \(0\) through \(6\) sum to \(21\), so if the three rows have equal sums, each row must sum to \(7\). Since there is no \(7\), the \(0\) cannot be placed in an outer row and still allow each row to total \(7\). Therefore, \(0\) must be in the middle row. Because the product of any row containing \(0\) is \(0\), the product of the numbers in the middle row is <strong>0</strong>.