Grades 7-8 Video Solutions 2026-2026_7-8

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Video Summary

Problem number 6, Jo wants to place the numbers 2, 0, 2, and 6 into the 4 boxes, with one number in each box to form the expression. When she calculates the result, what is the smallest positive value she can obtain? When we think about this fraction, to make it as small as possible, we want to make the numerator as small as possible, and make the denominator as large as possible, because then we have a small number divided by a large number, which will be very small. To do this, let's think about what the smallest possible value for the numerator is. Well, the smallest digit is 0, and the next smallest digit is 2, so the smallest possible value for the numerator is 2 plus 0. This leaves 6 minus 2, which is indeed the largest possible subtraction we can form in this problem. In this case, we can get that this value is equal to 2 divided by 4, which is also equal to 1 half. Therefore, the answer is D, 1 half.

Keywords

fraction

smallest positive value

numerator

denominator

number placement