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Grades 7-8 Video Solutions 2026
2026_7-8_06
2026_7-8_06
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Video Summary
Problem number 6, Jo wants to place the numbers 2, 0, 2, and 6 into the 4 boxes, with one number in each box to form the expression. When she calculates the result, what is the smallest positive value she can obtain? When we think about this fraction, to make it as small as possible, we want to make the numerator as small as possible, and make the denominator as large as possible, because then we have a small number divided by a large number, which will be very small. To do this, let's think about what the smallest possible value for the numerator is. Well, the smallest digit is 0, and the next smallest digit is 2, so the smallest possible value for the numerator is 2 plus 0. This leaves 6 minus 2, which is indeed the largest possible subtraction we can form in this problem. In this case, we can get that this value is equal to 2 divided by 4, which is also equal to 1 half. Therefore, the answer is D, 1 half.
Keywords
fraction
smallest positive value
numerator
denominator
number placement
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