Grades 7-8 Video Solutions 2026-2026_7-8

Video Transcription

Video Summary

The five squares have side lengths 1, 2, 3, 4, and 5, so their total area is \(1^2+2^2+3^2+4^2+5^2=55\).  <br />The cut removes triangle \(ABE\). Its base is the total width \(AE=15\), and its height is \(BE=1\), since the parallel lines make the vertical difference equal to \(5-4=1\).  <br />So the triangle’s area is \(\tfrac12 \cdot 15 \cdot 1=7.5\).  <br />Thus, the remaining area is \(55-7.5=47.5\text{ m}^2\).

Keywords

squares

area

triangle

geometry

measurement