Question number eight, the number n is the largest positive integer for which 4n is a three-digit number and m is the smallest positive integer for which 4m is a three-digit number. What is the value of 4n minus 4m? So let's suppose that we have just real numbers for now and solve the problem, then we'll find the integers that we need. So supposing that 4 times n is equal to 1,000, we have n is equal to 250, but that's too large because we need 4n to be a three-digit number. So we choose, we choose n to be equal to 249 so that 4n is less than 1,000. Similarly, supposing that 4 times m is a three-digit number, we set that equal to the smallest positive integer that has three digits, so 100. And we have the value for m equal to 25, and this is acceptable, anything smaller would not work. We then choose m equal to 25 because if m is less than 25, the quantity 4 times m would be less than 100, which is not what we want. So then we compute 4 times n minus m would be equal to 4 times 249 minus 25, and that after finishing the calculation would give us 896, and so the answer to problem number 8 is C.

integer

three-digit

calculation

positive

difference