Grades 9-10 Video Solutions 2014-Levels 9&10 Video Solutions 2014 problem21

Levels 9&10 Video Solutions 2014 problem21

Video Transcription

Video Summary

The problem involves the equation \( n \times u \times (m + b + e + r) = 33 \), where each letter represents a different digit from 0 to 9. Since 33 is 3 times 11, \( n \times u = 3 \) and \( m + b + e + r = 11 \). The digits for \( n \) and \( u \) must be 1 and 3. For \( m, b, e, \) and \( r \), the possible digits are 5, 4, 2, and 0, since larger digits don't fit the sum constraint. There are 24 permutations of 4 digits and 2 ways to assign \( n \) and \( u \), totaling 48 combinations. The solution is 48 ways.

Keywords

equation

digits

combinations

permutations

solution