Grades 9-10 Video Solutions 2021-video 2021 9-10/22

video 2021 9-10/22

Video Transcription

Video Summary

The problem involves numbers \(a\), \(b\), and \(c\) satisfying \(a + b + c = 0\) and \(abc = 78\). To find the value of \((a + b)(b + c)(c + a)\), we use algebraic manipulation, substituting \(a+b = -c\), \(b+c = -a\), and \(c+a = -b\). Simplifying, we find the expression equals \(-abc\), which is \(-78\). Therefore, the solution to the expression is \(-78\). Since the answer isn't listed in the options, it is "none of the above."

Keywords

algebra

expression

manipulation

solution

none