Grades 9-10 Video Solutions 2022-2022_9-10

Video Transcription

Video Summary

The problem involves calculating the area of triangle FPD formed by the diagonals of squares ABCD and EFGB, with lengths of 7 cm and 10 cm, respectively. Since P is the intersection of the diagonals of square ABCD, A is the midpoint of D and B, splitting the triangle into two equal parts. This makes the area of triangle FPD half of the area of the larger triangle formed by the diagonals. The area of this larger triangle is \( \frac{1}{2} \times 7 \times 10 = 35 \). Thus, the area of triangle FPD is \( \frac{35}{2} = 17.5 \, \text{cm}^2 \).

Keywords

triangle area

diagonals intersection

squares ABCD EFGB

geometry problem

triangle FPD