Grades 9-10 Video Solutions 2023-2023_9-10

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Video Summary

To determine which expression is odd given that \( m \) and \( n \) are both odd integers, we evaluate each option:<br /><br />- \( a: n(n + 1) \) is even since \( n + 1 \) is even.<br />- \( b: (m + 1)(n + 1) \) is even since both terms are even.<br />- \( c: m + n + 2 \) is even because \( m + n \) is even, and adding 2 keeps it even.<br />- \( e: m + n \) is even because the sum of two odd numbers is even.<br /><br />This leaves \( d: mn + 1 \). Here, \( mn \) is odd (the product of odd numbers is odd), and adding 1 gives an odd number. Therefore, \( d \) is the correct odd expression.

Keywords

odd integers

expression evaluation

mathematics

odd and even numbers

mn plus one