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Grades 9-10 Video Solutions 2023
2023_9-10_30
2023_9-10_30
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Video Transcription
Video Summary
Elizabeth can arrange the integers 1 to 9 in 9 boxes such that any 3 adjacent boxes sum to a multiple of 3 in \(6^4\) ways. To achieve this, she organizes the numbers into sequences of groups like \(a, b, c, a, b, c, a, b, c\), where \(a, b, c\) represent numbers equivalent to 0, 1, and 2 mod 3 respectively. There are 6 permutations of arranging \(a, b, c\), and for each residue class (numbers 3, 6, 9 for \(a\); 1, 4, 7 for \(b\); 2, 5, 8 for \(c\)), there are 6 possible arrangements. Therefore, the total arrangements are \(6 \times 6 \times 6 \times 6 = 1296\) ways.
Keywords
integer arrangement
adjacent boxes
multiple of 3
residue classes
permutations
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