Grades 9-10 Video Solutions 2025-2025_9-10

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Video Summary

The problem involves calculating the ratio of the area of a modified triangle to its original form. Initially, the triangle's base is denoted as \(b\) and height as \(h\), with its area being \((b \cdot h)/2\). The base increases by 50% to become \(3/2 \cdot b\) and the height decreases by one-third to \(2/3 \cdot h\). The new area is calculated as \((3/2 \cdot b) \cdot (2/3 \cdot h)/2\), simplifying back to \((b \cdot h)/2\), the same as the original area. Thus, the ratio of the new area to the original is 1:1.